Question

1 NH4NO2 (s) = 1 N2 (g) + 2 H2O (g)How many liters of nitrogen gas is produced if 25.5 L of water is produced at STP?

Answer 1

Step 1

The reaction must be written, completed, and balanced:

1 NH4NO2 (s) = 1 N2 (g) + 2 H2O (g)

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Step 2

It is assumed to be at STP conditions, therefore:

1 mole of any gas = 22.4 L (volume)

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Step 3

According to the reaction:

1 mole N2 (STP) = 22.4 L

1 mole H2O (STP) = 22.4 L

So,

1 x 22.4 L N2 ----------- 2 x 22.4 L H2O

X ----------- 25.5 L H2O

X = 25.5 L H2O x 1 x 22.4 L N/ 2 x 22.4 L H2O = 12.8 L N2

Answer: 12.8 L of N2