1 Answer

Jaclynn · Answer 1 · 2023-04-12T10:05:52+0000

Step-by-step explanation

Let's recall that to reflect a polygon it is sufficient to reflect its vertices. After reflecting them, we only need to join the resulting points by segments to get the reflection of the total quadrilateral.

With this in mind, let's reflect the four vertices of our figure over the given line.

Let's start with

$O=(1,0)\text{.}$

Firstly, we need to find the perpendicular line passing through O. It has the equation

$y_p=m\cdot x_p+b,$

where m is the slope, and b is the y-intercept. For we want the line to be perpendicular to the given one, we have

Then, the equation above becomes

$y_p=-2x_p+b\text{.}$

Now, O must lie in the line; then, ("we can evaluate the equation for O")

$0=-2(1)+b\text{.}$

Solving it for b, we get

$\begin{gathered} 0=-2(1)+b, \\ 0=-2+b, \\ 2=b, \\ b=2. \end{gathered}$

Thus, the equation for the line perpendicular to the given one passing through O is

Let's graph our current situation:

The green line represents the given line, and the blue line represents the perpendicular line, which equation we just found. Point B is the point where both lines intersect. The reflection of O over the provided line is point C, the point on the perpendicular line which is "as far from B as O".

Now, How to calculate C? Note that B is the middle point between C and O. Then, if

$(0,2)=B=((1+c_1)/(2),(0+c_2)/(2))\text{.}$

That is

$\begin{cases}(1+c_1)/(2)=0, \\ \\ (0+c_2)/(2)=2.\end{cases}$

Solving both equations, we get

$\begin{gathered} (1+c_1)/(2)=0,\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots.\text{ }(0+c_2)/(2)=2,\text{ } \\ 1+c_1=0,.\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots..(c_2)/(2)=2,_{} \\ {\textcolor{green}{c}_{\textcolor{green}{1}}\textcolor{green}{=-1}}.\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots\ldots...{\textcolor{green}{c}_{\textcolor{green}{2}}\textcolor{green}{=4}}. \end{gathered}$

Thus