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A baseball is covered with 42.3 cm2 of leather. Another larger baseball is to be constructed so that the ratio of the volume of the larger baseball to that of the smaller baseball is 16 over 3. What will be the surface area of the new baseball? Round your answer to the nearest tenth

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We are told that the volumes between two spheres is 16/3, this means that:


(V_1)/(V_2)=(16)/(3)

Now the formula for the volume of a sphere is:


V=(4\pi r^3)/(3)

Replacing in the previous formula:


((4\pi r^3_1)/(3))/((4\pi r^2_2)/(3))=(16)/(3)

Simplifying:


(r^3_1)/(r^3_2)=(16)/(3)

Now we solve for the first radius which is the radius of the bigger sphere:


r^3_1=(16)/(3)r^3_2

Now we determine the radius of the smallest ball using the formula for the surface area of a sphere:


A_S=4\pi r^2_2

Now we replace the value of the surface area:


42.3=4\pi r^2_2

Now we solve for the radius:


(42.3)/(4\pi)=r^2_2

Taking square root on both sides:


\sqrt[]{(42.3)/(4\pi)}=r_2

Solving the operation:


1.83\operatorname{cm}=r_2

Now we replace the value of the radius in the proportion:


r^3_1=(16)/(3)(1.83\operatorname{cm})^3

Solving the operations:


r^3_1=32.7\operatorname{cm}^3

Taking cubic root to both sides:


r_1=\sqrt[3]{32.7\operatorname{cm}^3}

Solving the operation:


r_1=3.19\operatorname{cm}

Now we use the formula for the surface area using the new radius:


A_S=4\pi r^2_1

Replacing the radius:


A_S=4\pi(3.19cm)^2

Solving the operation:


A_S=127.9\operatorname{cm}^2

Therefore, the surface area of the new ball is 127.9 square centimeters.

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