Question

Please help I’m literally crying!I’m questions 6-9, state the solutions for the quadratic equating depicted in the graph.

Answer 1

7) -6 and 1

Explanations:

The standard quadratic equation is expressed as:

`f(x)=ax^2+bx+c`

The expression in factored form is given as:

`f(x)=(x-a)(x-b)`

where a and b are zeros of the quadratic equation:

From the graph, the zeros of the function are the point where the curve cuts the x-axis. The zeros of the equation are -6 and 1

Substitute the given zeros into the factored form;

`\begin{gathered} f(x)=(x-(-6))(x-1) \\ f(x)=(x+6)(x-1) \\ f(x)=x^2-x+6x-6 \\ f(x)=x^2+5x-6 \end{gathered}`

Hence the solution of the quadratic equation depicted in the graph are -6 and 1