Question

Pls help... I need to write some words to post this​

Answer 1

k=100, n=3, 1.5625, 10

Explanation:

To find n and k, we can plug x and z in.

First we can try this for (1,100). We will get:

`100=(k)/(1^(n) )`

Since 1 to any power is 1, we can assume that the denominator is 1 and therefore k=100.

Armed with k=100, we can plug numbers into the second equation.

`12.5=(100)/(2^(n) )`

Moving
`{2^(n) }` to the left side, we get:

`2^n=(100)/(12.5) }=8`

therefore we can solve and we see that n=3.

We can do the same for x=4, but since we have n, k, and x, we can plug these in to get z

`z=(100)/(4^(3)) =1.5625`

We will do the same as previous but instead plug in x

`(1)/(10)=(100)/(x^(3) )`

We isolate
`x^(3)` and get

`x^(3) =1000`

Therefore x=10