1 Answer

Patrick Lumenus · Answer 1 · 2023-10-31T12:59:32+0000

We are given that the gravitational pull of mars is 0.376 times the gravitational pull of the earth. The gravitational pull of the earth is:

Now, we determine the gravitational pull of mars:

$g_{\text{mars}}=0.376g$

Substituting the value of "g" we get:

$g_{\text{mars}}=0.376(9.8(m)/(s^2))$

Solving the operation we get:

$g_{\text{mars}}=3.68(m)/(s^2)$

Now, to determine the weight of a person we use the following formula:

$W=mg_{\text{mars}}$

Where:

$\begin{gathered} W=\text{ weight} \\ m=\text{ mass} \end{gathered}$

Substituting the values we get:

$W=(98.6\operatorname{kg})(3.68(m)/(s^2))$

Solving the operation we get:

Therefore, the weight of the person on mars is 363.32 Newtons.

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