Question

The constant Keq Li2Co3 (s) arrows 2Li+(aq)+ Co3 2- (aq)

Answer 1

Step 1 - Discover which reactants or products are part of the equilibrium constant

The given reaction is the dissolution of Li2CO3, which can be represented as:

`Li_2CO_(3(s))\rightleftarrows2Li^+_((aq))+CO^(2-)_(3(aq))_{}`

In an equilibrium constant, only liquid, aquous or gas reactans or products will be considered. Therefore, Li2CO3, being a solid, will not be part of the dissolution equilibrium constant.

Step 2 - Set the equilibrium constant for the reaction

We know that an equilibrium constant is given by the quocient between products and reactants. In this case, since our reactant is a solid, it will not be taken into account. We have, then:

`K=\lbrack Li^+\rbrack^2\lbrack CO^(2-)_3\rbrack`

Remember: the concentration of Li(+) must be elevated to the power of 2 because, in the dissolution reaction, two moles of Li(+) are formed.