Answer
we are given the mass of C2H26 as 561.56grams. we are also given the pressure and volume as 100.03kPa and 47.08L respectively
to find the temperature, we first need to calculate the moles of C2H6 in 561.56 grams
we can use the following equation to find moles
moles = mass/ Molar mass
= 561.56grams / 30.07grams/mol
= 18.68 moles
now that we know that we have 18.68 moles we can determine the temperature using the ideal gas equation
PV = nRT
we can rearrange the equation to make T subject of the equation like this
T = PV/nR
P - pressure = 100.03kpa = 0.9872 atm
1 atm = 101.325kpa
therfore 100.03kps/101.325kps
= 0.9872 atm
V - volume = 47.08L
n - moles = 18.68 moles
R - gas constatnt (0.082057 L atm mol-1 K-1)
therefore
T = (0.9872atm x 47.08L)/ (18.68 mol x 0.08206)
= 30.32K