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Need help finding the answer to see where i went wrong(15)

Need help finding the answer to see where i went wrong(15)-example-1
User Sam Wilson
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Given that a line has its x-intercept as -8 and its y-intercept as 5, we can determine the slope of a line perpendicular to this line below.

Step-by-step explanation

We can derive two points that the given line passes through using the x and y-intercept. This can be expressed as;


\begin{gathered} x_1,y_1=(-8,0) \\ x_2,y_2=(0,5) \end{gathered}

Therefore using the slope formula we would have;


m=(y_2-y_1)/(x_2-x_1)=(5-0)/(0-(-8))=(5)/(8)

For two lines to be perpendicular, their slope can be expressed as;


\begin{gathered} m_1m_2=-1 \\ \therefore taking\text{ the slope of the given line as }m_1 \\ (5)/(8)* m_2=-1 \\ (5m_2)/(8)=-1 \\ 5m_2=-8 \\ m_2=-(8)/(5) \end{gathered}

Answer:


m_(2)=-(8)/(5)

User Janpan
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