1 Answer

Christopher Slater · Answer 1 · 2023-10-16T03:23:39+0000

Given:

volume of the rock is

$V=6.0\text{ cm}^3$

The mass of the rock is

$m=30.0\text{ g}$

Required: Density of the rock is to be calculated

Step-by-step explanation:

To calculate the density of the rock we will use the formula that is given as

$\rho=(m)/(V)$

first, change the respective quantities in SI form

then volume of the rock is

$\begin{gathered} V=6.0\text{ cm}^3 \\ V=6.0\text{ cm}^3\text{ }*\frac{1\text{ m}^3}{10^6\text{ cm}^3} \\ V=6.0*10^(-6)\text{ m}^3 \end{gathered}$

Similarly for mass of the rock

then

$\begin{gathered} m=30.0\text{ g}*\frac{1\text{ kg}}{10^3\text{ g}} \\ m=30.0*10^(-3)\text{ Kg} \end{gathered}$

plugging all the values in the above relation, we get

$\begin{gathered} \rho=(m)/(V) \\ \rho=\frac{30.0*10^(-3)\text{ Kg}}{6.0*10^(-6)\text{ m}^3} \\ \rho=500.0\text{ kg/m}^3 \end{gathered}$

Thus, the density of the rock is

$500.0\text{ kg/m}^3$

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