We have the system of equations:

We can clear y from the first equation and replace it in the second:


We have two solutions for x: x1=0 and x2=5.
Then, we can calculate the solutions for y:

Then, the solutions are (0,5) and (5,0).
Answer: We have two solutions. One solution is x=0 and y=5 and the other solution is x=5 and y=0.