The Solution:
Let the number of True/False questions in the assessment be represented with x.
And the number of multiple-choice questions be represented with y.
Given that the total number of questions is 20.
We have,

Given that each True/False question is worth 3 points while each multiple-choice question is worth 11 points and the total value of the whole question is 100 points.
We have,

We are required to find the number of the True/False questions (x) and the number of multiple-choice questions (y).
Solving the eqn(1) and eqn(2) simultaneously by the Substitution Method, we have from eqn(1) that:

Putting eqn(3) into eqn(2), we get

Collecting the like terms, we get

Dividing both sides by -8, we get

So, the number of True/False questions in the assessment is 15.
To find x, we shall substitute 15 for x in eqn(3)

Thus, the assessment has 5 multiple-choice questions.