51.1k views
3 votes
Read the problem below and solve the solution draw a diagram on your paper to help solve it

Read the problem below and solve the solution draw a diagram on your paper to help-example-1

1 Answer

4 votes

Answer:

The number of handshakes that will be there is;


15\text{ }

Step-by-step explanation:

Given that there are 6 people in the party.

And each person must shake hands with every other person exactly once.

So, since order is not improtant, we have;


^nC_r=(n!)/(r!(n-r)!)

For this question;


\begin{gathered} n=6 \\ r=2\text{ ( the number of persons involved in a single hand shake)} \end{gathered}

It then becomes;


\begin{gathered} ^6C_2=(6!)/(2!(6-2)!)=(6!)/(2!*4!) \\ ^6C_2=(1*2*3*4*5*6)/(1*2*1*2*3*4)=(30)/(2) \\ ^6C_2=15 \end{gathered}

Therefore, the number of handshakes that will be there is;


15\text{ }

User Sanjay Shr
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories