1 Answer

Jcburns · Answer 1 · 2023-03-01T16:01:06+0000

Solution:

Given:

$\begin{gathered} (x+y)^2=1 \\ x^2+y^2=1 \\ x+y\leq0 \end{gathered}$

The graph of the functions is given below;

From the graph, the points that satisfy the conditions are;

$(0,-1)\text{ and }(-1,0)$

Therefore, the final answer is Two.

OPTION B.

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