Question

Using electronegativity values, classify the bond between each of the following pairs of atoms as nonpolar covalent, or ionic and label each polarcovalent bond with + and - andshow the direction of the dipole: K and o As and clN and NP and Br

Answer 1

K and O: ionic

As and Cl: polar covalent

N and N: nonpolar covalent

P and Br: polar covalent

Step-by-step explanation:

If the difference between the electronegativity of the atoms is less than 0.4 it will be a nonpolar covalent bond. If the difference is bigger than 1.7 the bond will be ionic. In the middle, the bond will be polar covalent.

• K and O,:

- K electronegativity: 0.8

- O electronegativity: 3.5

Difference: 3.5-0.8 = 2.7 (ionic)

• As and Cl,:

- As electronegativity: 2.0

- Cl electronegativity: 3.0

Difference:3.0-2.0 = 1.0 (polar covalent)

• N and N,:

- N electronegativity: 3.0

Difference: 3.0-3.0 = 0 (nonpolar covalent)

• P and Br,:

- P electronegativity: 2.1

- Br electronegativity: 2.8

Difference: 2.8-2.1 = 0.7 (polar covalent)