ANSWER:
20 bacteria, 85%
Explanation:
We have that the function that models the situation is the following:
![\begin{gathered} s\left(n\right)=20·b^n \\ \\ b=1.85 \\ \\ \text{ Therefore:} \\ \\ s(n)=20\cdot(1.85)^n \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/32h64skcxvi4x1eknbdemwfgdctkxx1z9a.png)
An exponential equation has the following form:
![y=A_0\cdot(1+r)^n](https://img.qammunity.org/2023/formulas/mathematics/college/l53am7ep3myd6ns1l70lqt8qhzne9422di.png)
Where A0 is the initial value and r is the growth rate, therefore:
![\begin{gathered} A_0=20 \\ \\ 1+r=1.85 \\ \\ r=1.85-1=0.85 \\ \\ r=85\% \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3r3ooh9k5rxd96y9frt593mi2lp0a1xu5a.png)
Therefore:
Based on model, there were initially 20 bacteria.
If b = 1.85, the hourly percent growth rate of the bacteria would be 85%