We are given the following information:
Will is w years old
Ben is 3 years older
1. This is expressed as:

2. Jan is twice as old as Ben. This is given as:

3. If you add together the ages of Will, Ben, and Jan the total comes to 41 years. This is given as:

4. In how many years time will Jan be twice as old as will? This is solved as shown below:

We will proceed to solve:
![\begin{gathered} j=22,w=8 \\ In\text{ ''x'' years, Jan will be twice as old Will (let the number of years be represented as ''x''). This is given by:} \\ j+x=2(w+x) \\ 22+x=2(8+x) \\ 22+x=16+2x \\ \text{Put like terms together, we have:} \\ 2x-x=22-16 \\ x=6 \\ \\ Check\colon In\text{ 6 years time,} \\ Jan=22+6=28\text{ years} \\ Will=8+6=14\text{ years} \\ 28=2\cdot14\Rightarrow28=28(TRUE) \\ \end{gathered}]()
Therefore, Jan will be twice as old as Will in 6 years time