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Solve (t+2)^3/4 =2 where t is a real number.t=

User Serra
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1 Answer

4 votes

To solve


(t+2)^{(3)/(4)}=2

for t, first, we raise the equation to the power of four:


(t+2)^3=2^4\text{.}

Simplifying we get:


(t+2)^3=16.

Therefore:


t+2=\sqrt[3]{16}.

Finally, we get:


t=\sqrt[3]{16}-2=\sqrt[3]{8\cdot2}-2=2\sqrt[3]{2}-2=2(\sqrt[3]{2}-1)\text{.}

Answer:


t=2(2^{(1)/(3)}-1)\text{.}

User Bobbles
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