We want to solve the following equation
![2\cdot(x-3)+7=6](https://img.qammunity.org/2023/formulas/mathematics/college/tf1g8cjmix50tccd48ga8440ktwxt0t3ph.png)
First, we start by distributing the multiplication on the left side, so we have
![2x-6+7=6](https://img.qammunity.org/2023/formulas/mathematics/college/57domrond9vmdpbuqhjrrr3p4q3w2991qt.png)
Note that if we compare this step to the second step of the given procedure, the mistake occured on the distribution of the multiplication. So, instead of writing -6, the mistake was to write -3.
Now, we continue to solve the equation from this point. First, we operate on the left side, so we get
![2x+1=6](https://img.qammunity.org/2023/formulas/mathematics/college/mo7nxg2icus7q4hp7jd0nwdxtfferry0ne.png)
Now, we subtract 1 from both sides
![2x=6-1=5](https://img.qammunity.org/2023/formulas/mathematics/college/plfnfahblq3dwuyhbhi6pibvmmu8jwwb1a.png)
Then, we divide both sides by 2. So we get
![x=(5)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/rpyud9cdfyy8fc75lkn3e23mntxvx060o4.png)