Answer:
![x=1](https://img.qammunity.org/2023/formulas/mathematics/high-school/xsb7940fuqxllob7pwpm2jsl9ruu78r3uv.png)
Explanation:
![1+(3x-3)=1](https://img.qammunity.org/2023/formulas/mathematics/college/izhei5665sijcp7ddv20gfofbdxj86uipa.png)
First, you have to take the one that is outside of the Parenthesis and take it to the other side. That would mean it would be this:
![3x-3=1-1](https://img.qammunity.org/2023/formulas/mathematics/college/s99mh34u9ly62a0klrkcu7tqreuyy9clrd.png)
1 - 1 is 0
![3x-3=0\\](https://img.qammunity.org/2023/formulas/mathematics/college/svsrnu1jfureg6jlkreramxrfhn5wg5za7.png)
Move the -3 to the other side, which makes it positive;
![3x=3](https://img.qammunity.org/2023/formulas/mathematics/college/szon2pce64nmw35dm1n4mx4d60vwm5h4w4.png)
Divide both sides by 3
![x=1](https://img.qammunity.org/2023/formulas/mathematics/high-school/xsb7940fuqxllob7pwpm2jsl9ruu78r3uv.png)
If you want to check it, you can replace 1 in the original equation:
![1+(3X1-3)=1](https://img.qammunity.org/2023/formulas/mathematics/college/sitk6rfal0sopanefrd62wi0ophfct9x97.png)
![1+(0)=1](https://img.qammunity.org/2023/formulas/mathematics/college/ajdjuhnjceoi4u70qirrm4gx2j1noe8546.png)
![1=1](https://img.qammunity.org/2023/formulas/mathematics/college/hj1knjdgisxzn6oawkz9raxocsrd83h4c8.png)
So x=1