Question

9 1 point A bowl contained 13 red and brown M&M's. There was one more red M&M's than brown M&M's. How many red M&M's are in the bowl?

Answer 1

We know that there were 13 M&Ms in total.

`r+b=13`

Where r represents red M&Ms, and b represents brown M&Ms.

"There was one more red M&M than brown M&M", we can express this as

`r=b+1`

Then, we combine the equations we've got to solve for b

`\begin{gathered} r+b=13 \\ b+1+b=13 \\ 2b=13-1 \\ 2b=12 \\ b=(12)/(2) \\ b=6 \end{gathered}`

Then, we find r

`r=6+1=7`

Hence, there were 6 brown M&Ms and 7 red M&Ms.