Question

a ball is thrown vertically upward. after t seconds, it's height h ( in feet) is given by the function h(t) =80t -16t^2. what is the maximum height that the ball with reach. Do not round answer. Height:

Answer 1

For this case we have the following function:

`h(t)=80t-16t^2`

For this case the maximum occurs when t=0 and we can find the maximum with the first derivate like this:

`80-32t=0`

Solving for t we got:

`t=(80)/(32)=(5)/(2)`

Then the maximum height is:

`h(2.5)=80\cdot2.5-16(2.5)^2=100`