2.8k views
4 votes
Consider the equation 8x + 4y = 64.Where does the graph intersect the y-axis?

Consider the equation 8x + 4y = 64.Where does the graph intersect the y-axis?-example-1
User Stytown
by
4.9k points

1 Answer

3 votes

we have the equation

8x + 4y = 64

REmember that

The y-intercept is the value of y when the value of x is equal to zero

so

Find the y-intercept

For x=0

substitute in the equation

8(0) + 4y = 64

4y=64

Solve for y

y=64/4

y=16

therefore

The graph intersect the y-axis at point (0,16)

Part 2

8x + 4y = 64

Solve for y -----> that means, isolate the variable y

so

step 1

subtract 8x both sides

8x + 4y -8x= 64-8x

4y=64-8x

step 2

Divide by 4 both sides

4y/4=(64-8x)/4

simplify

y=16-2x

Rewrite

y=-2x+16

Part 3

User Scratte
by
4.7k points