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Contains the points (2,5) and (6, 21); slope-intercept form

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In order to find the line equation, first consider that you can write the general equation of a line as follow:

y - yo = m(x - xo)

where m is the slope and (xo,yo) is any point on the line.

Calculate the slope m by using the following formula:


m=(y_2-y_1)/(x_2-x_1)

where (x1,y1) and (x2,y2) are any points on the line.

In this case, you have:

(x1,y1) = (2,5)

(x2,y2) = (6,21)

Replace the previous values of the parameters into the formula for m:


m=(21-5)/(6-2)=(16)/(4)=4

Now, use (xo,yo) = (2,5) and the previous value of m into the general equation for a line, and then solve for y, as follow:


\begin{gathered} y-5=4(x-2) \\ y-5=4x-8 \\ y=4x-8+5 \\ y=4x-3 \end{gathered}

The previous result is the required equation in slope-intercept form.

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