Logarithmic expressions

asked Aug 21, 2023 151k views

1 vote

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4 votes

N 1

we have

$\log _220=\log _2(2^2\cdot5)=2\log _22+\log _25=2+\log _25$

N 2

we have

$\log _224=\log _2(2^3\cdot3)=3\log _22+\log _23=3+\log _23$

N 3

$\log _248=\log _2(2^4\cdot3)=4\log _22+\log _23=4+\log _23$

$\log _240=\log _2(2^3\cdot5)=3\log _22+\log _25=3+\log _25$

Bohr answered Aug 25, 2023

by Bohr

4.5k points

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