Question

6. A photographer points a camera at a window in a nearby building forming an angle of 46° withthe camera platform. If the camera is 59 meters from the building, how high above the platformis the window? Round to two decimal places.

Answer 1

From the problem, the angle of inclination of the camera from the platform to the window of a nearby building is 46 degrees and is 59 meters apart.

The illustration will be :

As you can see, we can form a right triangle.

Using the tangent function :

`\tan \theta=\frac{\text{opposite}}{\text{adjacent}}`

The tangent of an angle is equal to the opposite side to the angle divided by the adjacent side to the angle.

The angle is 46 degrees and the adjacent side is 59 meters.

Solve for the opposite side which is the height of the window.

`\begin{gathered} \tan 46=\frac{\text{opposite}}{59} \\ \text{opposite}=59\tan 46 \\ \text{opposite}=61.096 \end{gathered}`

The answer rounded to two decimal places is 61.10 meters