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19 votes
19 votes
What is the equation of the line with a slope of 4 and passes through the point (1, -4)?

User David Segonds
by
3.2k points

2 Answers

20 votes
20 votes

Answer: y = 4x - 8

Explanation:

The best way to go about this is to first put the information you know into point-slope form, which is:


y-y_(1) =m(x-x_(1))


y_(1) and
x_(1) represent the values of our point (1, -4), so:


y_(1)=-4, and
x_(1)=1.


m represents our slope of 4, so:


m=4

From this, we can plug in our values:


y-(-4)=4(x-1)

A little simplification and distrobution takes us to this:


y+4=4x-4

Then simply subract 4 from both sides to get this:


y=4x-8

An easier way to reason this is to visualize the line in your head and figuring out what the y-intercept is so you can go strait into the
y=mx+b form where b is the y-intercept.

User Oakad
by
3.4k points
16 votes
16 votes

Answer:

y=4x-8

Explanation:

m=4 (1,-4)

-4=4(1) + c

-4=4+c

-4-4=c

-8=c

y=4x-8

User Tiandra
by
3.0k points