Question

What is the axis of symmetryF(x)=x2+3

Answer 1

The function:

`f(x)=x^2+3`

has the form:

`f(x)=ax^2+bx+c`

with a = 1, b = 0, and c = 3.

The equation of the axis of symmetry is calculated as follows:

`x=(-b)/(2a)`

Substituting with a = 1, b = 0, we get:

`\begin{gathered} x=(-0)/(2\cdot1) \\ x=0 \end{gathered}`