If y varies jointly as x and z when x = 5, y = 80, and z = 8. what is y when x = 16 and z = 2?

Question

asked Dec 11, 2023 27.2k views

1 Answer

Patrick Kostjens · Answer 1 · 2023-12-16T00:24:04+0000

We are given that y varies jointly as x and z

Mathematically,

Where k is the constant of proportionality.

When x = 5, y = 80, and z = 8

$\begin{gathered} y=kxz \\ 80=k\cdot5\cdot8 \\ k=(80)/(5\cdot8) \\ k=2 \end{gathered}$

So, the relationship becomes

What is y when x = 16 and z = 2?

$\begin{gathered} y=2xz \\ y=2\cdot16\cdot2 \\ y=64 \end{gathered}$

Therefore, the value of y is 64