Question

Tony twirls a pizza dough overhead. It is rotating at 0.65 m/s. If the pizza dough has a radius of 0.10 m and a mass of 0.50 kg, what centripetal force is it experiencing?

Answer 1

Given,

The linear velocity of the pizza dough, v=0.65 m/s

The radius of the pizza dough, r=0.10 m

The mass of the pizza dough, m=0.50 kg

The centripetal force of an object is given by the equation,

`F=m(v^2)/(r)`

On substituting the known values in the above equation,

`\begin{gathered} F=0.50*(0.65^2)/(0.10) \\ =2.11\text{ N} \end{gathered}`

Thus the centripetal force experienced by the pizza dough is 2.11 N