Ok, so
Remember that:
For any quadratic equation of the form:

- If the leading coefficient is greater than zero, the parabola opens upward, and
- If the leading coefficient is less than zero, the parabola opens downward.
So, here we have the following functions:

The leading coefficient is greater than zero, so this parabola opens upward.
Option B:

The leading coefficient is less than zero, so this parabola opens downward.
Option C:

The leading coefficient is greater than zero, so this parabola opens upward.
Option D:

The leading coefficient is less than zero, so this parabola opens downward.
Therefore, the correct options are B and D.