Question

A student increases the temperature of a 457 cm3 balloon from 270 K to 585 K.Assuming constant pressure, what should the new volume of the balloon be?Round your answer to one decimal place.

Answer 1

Given:

The initial volume of the balloon, V₁=457 cm³=457×10⁻⁶ m³

The initial temperature of the balloon, T₁=270 K

The final temperature of the balloon, T₂=585 K

To find:

The new volume of the balloon.

Step-by-step explanation:

From Charle's law,

`(V_1)/(T_1)=(V_2)/(T_2)`

Where V₂ is the new volume of the balloon.

On substituting the known values,

`\begin{gathered} (457*10^(-6))/(270)=(V_2)/(585) \\ \Rightarrow V_2=(457*10^(-6))/(270)*585 \\ =990*10^(-6)\text{ m}^3 \\ =990\text{ cm}^3 \end{gathered}`

Final answer:

Thus the new volume of the balloon is 990 cm³