Question

Not a timed or graded assignment. Quick answer showing what whole numbers I need to put in = amazing review

Answer 1

`CF_4+2Br_2\text{ }\rightarrow CBr_4+2F_2`

STEP-BY-BY STEP EXPLANATION:

Given equation

`CF_4+Br_2\text{ }\rightarrow CBr_4+F_2`

To balance the above equation, we will need to apply the law of conservation of mass

The next process is to assign variables to each of the reactants and products

`\text{aCF}_{4\text{ }}+bBr_2\text{ }\rightarrow cCBr_4+dF_2`

For carbon

we have 1 carbon atom at the reactant side and 1 carbon atom on the product side

Mathematically

a = c

For Fluorine

We have 4 atoms of fluorine at the reactant side and 2 atoms of fluorine at the product side

4a = 2d

For Bromine

we have 2 atoms of bromine on the reactant side and 4 bromine atoms on the product side.

2b = 4c

Since a = c

Therefore, a = 1 and c = 1

2b = 4c

Recall that, c = 1

2b = 4

Divide both sides by 2

2b/2 = 4/2

b = 2

we also know that, 4a = 2d

a = 1

4(1) = 2d

4 = 2d

Divide both sides by 2

4/2 = 2d/2

d = 2

Therefore,

a = 1

b = 2

c = 1

d = 2