1 Answer

Gchen · Answer 1 · 2023-12-29T09:18:10+0000

To solve this question we will use the following expression to compute the theoretical probability:

$\frac{\text{favorable cases}}{total\text{ cases}}\text{.}$

Now, recall that the possible outcomes of rolling a die are 1, 2, 3, 4, 5, and 6. Therefore the probability of obtaining no 6 in each rolling is:

$(5)/(6)\text{.}$

Then, the probability of obtaining no 6's in four rollings is:

$(5)/(6)*(5)/(6)*(5)/(6)*(5)/(6)\text{.}$

Simplifying the above product we get:

$(5^4)/(6^4)=(625)/(1296)\text{.}$

Answer:

$(625)/(1296)\text{.}$

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