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Ayana has $20.95 in quarters and dimes. If she has 103 coins in all. find the number of quarters and dimes. * SHE HAS 103 COINS IN ALL!Help me!!

User Bangkokian
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Ayana has $20.95 in quarters and dimes. If she has 103 coins in all. find the number of quarters and dimes. * SHE HAS 103 COINS IN ALL!

Let

x -----> the number of quarters

y ----> the number of dimes

we have that

x+y=103

x=103-y ------> equation A

Remember that

1 quarter=$0.25

1 dime=$0.10

so

0.25x+0.10y=20.95 ------> equation B

Solve the system of equations

substitute equation A in equation B

0.25(103-y)+0.10y=20.95

solve for y

25.75-0.25y+0.10y=20.95

0.15y=25.75-20.95

0.15y=4.8

y=32

Find the value of x

x=103-32

x=71

therefore

the answer is

71 quarters and 32 dimes

User Pavitran
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