The total surface area is the sum of:
The Area of the rectangle on the base (36*40) = 1440 cm^2
Two triangles rectangles on the sides: 2*(36*27)/2 = 972 cm^2
One rectangle on the back of the figure: (40*27) = 1080 cm^2
And finally a inclined rectangle of base 40 and side we don't know but we can calculate: the side of this rectanlge is the hypotenuse ot the triangle rectangle of the side, so
![\text{hypotenuse = }\sqrt[]{36^2+27^2\text{ }}\text{ =}\sqrt[]{1296+729}=\sqrt[]{2025}=45](https://img.qammunity.org/2023/formulas/mathematics/high-school/z429ippglhot23gtjkyi0jzfc6ndchazkb.png)
Therefore the area of the inclined rectangle is (40*45) = 1800 cm^2
Total area = 1440+972+1080+1800 = 5292 cm^2
Answer:
5292 cm^2