1 Answer

Dietmar Winkler · Answer 1 · 2023-01-16T16:58:07+0000

Given the figure of a cone inside a cylinder

The volume of the space between the cylinder and the cone = the volume of the cylinder - the volume of the cone

The volume of the cylinder =

$\pi\cdot r^2\cdot h$

The volume of the cone =

$(1)/(3)\cdot\pi\cdot r^2\cdot h$

So, the volume of the space between them =

$\pi\cdot r^2\cdot h-(1)/(3)\pi\cdot r^2\cdot h=(2)/(3)\pi\cdot r^2\cdot h$

As shown in the figure: r = 4/2 = 2 in

h = 6 in

Let pi = 3.14

So, substitute with r, h, and pi

The volume of the space =

$(2)/(3)\cdot3.14\cdot2^2\cdot6=50.24$

Rounding to the nearest whole number

So, the answer will be option B) 50 in^3

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