We must graph and find the intercepts with the y-axis of the following equations:
A) Y = 3X - 6
B) Y = -0.6X + 2
C) Y = 1/4X - 5/4
All equations above are of the form Y = mx + b
where, b is the vertical intercept or the intercept with the y-axis
Now, let's start with equation A
A) Y = 3X - 6
to graph we need to locate two points
the two easiest points are when X = 0 and the other is when Y = 0
let's make x=0
![\begin{gathered} Y=3\cdot0-6 \\ Y=-6 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/luweqfp1tkkb3pw74hy6ia44v6nezeqw48.png)
so our first point in the graph is (0,-6)
now, when Y=0
![\begin{gathered} 0=3x-6 \\ 6=3x \\ (6)/(3)=x \\ x=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/uug072fdp1hdz5tuul4fhb2wnhi71pbuyw.png)
so, our second point is (2,0)
now that we know that the equation Y = 3X - 6 passes through the points (0, -6) and (2,0), we only have to join them with a straight line
B) Y = -0.6X + 2
when x=0, then y = 2
therefore point 1 is (0,2), which corresponds to the vertical intercept
for our second point: when y=0, then...
![\begin{gathered} 0=-0.6x+2 \\ -2=-0.6x \\ (-2)/(-0.6)=x \\ x=3.33 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/2ywfsam320qnit0vvra91ps9xn6c6bfdy9.png)
therefore our second point is (3.33 , 0) or as a fraction (10/3 , 0)
this is how the graph will look like