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Solve for the value of xAngle A: 3x+20Angle B:5x-12a. 21.5b. 12.25c. 16d. 20
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Solve for the value of xAngle A: 3x+20Angle B:5x-12a. 21.5b. 12.25c. 16d. 20

User Martin Konecny
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1 Answer

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* Assuming the angles are supplementary

(3x +20) + (5x - 12) = 180º

3x + 20 + 5x -12 = 180º

8x + 8 = 180

8x = 180 -8

x= 172/ 8

x= 21. 5

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Answer

x= 21. 5

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Solve for the value of xAngle A: 3x+20Angle B:5x-12a. 21.5b. 12.25c. 16d. 20-example-1
User Miko Kronn
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