Question

An object accelerates at a rate of -3.2 m/s^2 to a velocity of 8 m/s over a time of 14 s. What was its initial velocity?

Answer 1

`\text{Given that,}\\\\\text{Acceleration, a = -3.2 m s}^(-2)\\\\\text{Time, t = 14 sec}\\\\\text{Velocity, v = 8 m s}^(-1)\\\\\text{Initial velocity, v}_0 = ?\\\\\\v = v_0 +at\\\\\implies v_0 = v -at = 8 -(-3.2)(14) = 8 + 44.8 =52.8~ \text{m s}^(-1)`