Question

Which of the following is a possible solution for 2m2 + 11m + 15 = 0 ?2 =52.x = -5Cx = 6X = -3

Answer 1

The possible solution of the qudaratic function is x = -3

Step-by-step explanation

Given the below quadratic function

`\begin{gathered} 2m^2\text{ + 11m + 15 = 0} \\ \text{The standard form of quadratic function is given as} \\ ax^2\text{ + bx + c = 0} \\ \text{a = 2, b = 11, and c = 15} \\ \text{ Find ac } \\ ac\text{ = 2 }\cdot\text{ 15} \\ ac\text{ =30} \\ \text{ The factor of 30 that will give 11 when add and give 30 when multiply is 6 and 5} \\ 2m^2\text{ + 5m + 6m + 15 = 0} \\ m(2m\text{ + }5)\text{ + 3}(2m\text{ + 5) = 0} \\ (m\text{ + 3) (2m + 5) = 0} \\ (m\text{ + 3) = 0 or (2m + 5) =0} \\ m\text{ + 3 = 0 or 2m + 5 = 0} \\ \text{m = 0 - 3 or 2m = 0 - 5} \\ \text{m = -3 or 2m = -5} \\ \text{m = -3 or m = -5/2} \end{gathered}`

Therefore, the possible solution is -3