Question

Team X has a 40% chance of winning a game against team Y and team A has a 25% chance of winning a game against team B. What is the probability of team X and team A winning their respective games.?

Answer 1

Given:

Team X has a 40% chance of winning a game against team Y and team A has a 25% chance of winning a game against team B.

Required:

What is the probability of team X and team A winning their respective games?

Step-by-step explanation:

The concept required:

`Probability(P)=\frac{\text{ Number of favorable outcomes}}{\text{ Number of total outcomes}}`

So,

`\begin{gathered} P(X\text{ winning agianst }Y)=(40)/(100) \\ =(2)/(5) \end{gathered}`

And

`\begin{gathered} P(A\text{ winning against }B)=(25)/(100) \\ =(1)/(4) \end{gathered}`

Answer:

Completed the answer.