Question

Enter an equation in point-slope form for the line.(0, 3) and (2,6) are on the line.An equation of the line in point slope form is:

Answer 1

The Point-Slope form of an equation of the line, is:

`y-y_1=m\mleft(x-x_1\mright)`

Where "m" is the slope and this is a point of the line:

`(x_1,y_1)`

The formula for calculate the slope, is:

`m=(y_2-y_1)/(x_2-x_1)`

In this case, you can set up that:

`\begin{gathered} y_2=6 \\ y_1=3 \\ x_2=2 \\ x_1=0 \end{gathered}`

Substituting values, you get that the slope of the line is:

`\begin{gathered} m=(6-3)/(2-0) \\ \\ m=(3)/(2) \end{gathered}`

Knowing the slope and the point (2,6), you can susbtitute values into the equation in Point-Slope form shown at the beginning of the explanation.

Therefore, the answer is:

`y-6_{}=(3)/(2)(x-2)`