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The centers of two circles with radii 5 and 7 are 14 units apart. Find the length of the commonexternal tangent.

The centers of two circles with radii 5 and 7 are 14 units apart. Find the length-example-1
User Abhijeet
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2 Answers

3 votes

Since the centers of two circles with radii 5 and 7 are 14 units apart, the length of the common external tangent is equal to
2 √(13) units.

In Mathematics and Geometry, Pythagorean theorem is an Euclidean postulate that can be modeled or represented by the following mathematical equation:


c^2=a^2+b^2

Where:

  • a is the opposite side of a right-angled triangle.
  • b is the adjacent side of a right-angled triangle.
  • c is the hypotenuse of a right-angled triangle.

In order to determine the length of the common external tangent, we would have to apply Pythagorean's theorem as follows;


Length \;of\;the\; common\;external \;tangent=√((distance \;between\;centers )^2-(radii\;sum)^2) \\\\Length \;of\;the\; common\;external \;tangent=√((14 )^2-(7+5)^2) \\\\Length \;of\;the\; common\;external \;tangent=√(196-144)\\\\Length \;of\;the\; common\;external \;tangent=√(52)\\\\Length \;of\;the\; common\;external \;tangent=√(4) * √(13) \\\\Length \;of\;the\; common\;external \;tangent=2 √(13) \;units

User James Andrew
by
3.4k points
4 votes

Solution

Using the pythagoras


\begin{gathered} x^=√(14^2+2^2) \\ x^=√(200) \\ x=10√(2) \end{gathered}

The length of the common external tangent is


10√(2)=\text{ 14.14213}

The final answer


\:14.14213

The centers of two circles with radii 5 and 7 are 14 units apart. Find the length-example-1
User Ufoguy
by
3.3k points