65,682 views
42 votes
42 votes
Which of the following equations results in no solutions?

A 3(v + 5) = 2v - 4 + v
B 3(v + 5) = 2v + 15 + v
C 3(v + 5) = 2v + 15
D 3(v + 5) = 2v - 4

User Earline
by
2.7k points

2 Answers

5 votes
5 votes
A. This gives us 3v + 15 = 3v - 4. This is no solutions because the slope is the same and the y-intercept is different.
User Jeremy List
by
2.8k points
23 votes
23 votes

Answer:


\boxed{\sf A) \:3(v + 5) = 2v - 4 + v}

Explanation:


\sf A )\:3(v + 5) = 2v - 4 + v

Combine like terms:


\sf 3\left(v+5\right)=3v-4

Expand:


\sf 3v+15=3v-4

Subtract 15 from both sides:


\sf 3v+15-15=3v-4-15


\sf 3v=3v-19

Subtract 3v from both sides:


\sf 3v-3v=3v-19-3v


\sf 0=-19


\boxed{\sf{No\:Solution}}

_________________


\sf B )\:3(v + 5) = 2v + 15 + v

Combine like terms:


\sf 3\left(v+5\right)=3v+15

Expand:


\sf 3v+15=3v+15

Subtract 15 from both sides:


\sf 3v+15-15=3v+15-15


\sf 3v=3v

Subtract 3v from both sides:


\boxed{\sf 0=0}

_______________________


\sf C)\: 3(v + 5) = 2v + 15

Expand:


\sf 3v+15=2v+15

Subtract 15 from both sides:


\sf 3v=2v

Subtract 2v from both sides:


\sf 3v-2v=2v-2v


\boxed{\sf v=0}

_______________________


\sf D)\: 3(v + 5) = 2v - 4

Expand:


\sf 3v+15=2v-4

Subtract 15 from both sides:


\sf 3v+15-15=2v-4-15


\sf 3v=2v-19

Subtract 2v from both sides:


\sf 3v-2v=2v-19-2v


\boxed{\sf v=-19}

___________________________

User Crazybyte
by
2.9k points
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