The tangen of an angle in a triangle is given by:
![\tan \theta=\frac{\text{opp}}{\text{adj}}](https://img.qammunity.org/2023/formulas/mathematics/college/3fqrplha6xpdtt3tqrhu2iufem1jq7g70s.png)
where opp and adj means the opposite and adjacent legs, respectively.
In this case we have that:
![\tan G=(EF)/(FG)](https://img.qammunity.org/2023/formulas/mathematics/college/clyng0sy5u0yevp995tox8vmy7s7sp6im9.png)
then we need to find the length of leg EF. Using the pythagorean theorem we have:
![\begin{gathered} (√(24))^2=EF^2+3^2 \\ EF^2=(√(24))^2-3^2 \\ EF^2=15 \\ EF=\sqrt[]{15} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mcpiaj1oyulwz6g0cly44ljdgn0dt8a4zb.png)
Now that we know the leg we need we have that:
![\begin{gathered} \tan G=\frac{\sqrt[]{15}}{3} \\ \tan G=1.29 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/jf4rvzqlp6ylyls1howmn5rnpngsui1kd1.png)
Therefore the tangent of G is 1.29