Given:
![y=√(3x-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/oabhb8o1bnvyboc8qfguq74fe2to0elswn.png)
Required:
We need to find the rate of change of the given equation.
Step-by-step explanation:
Consider the given equation.
![y=√(3x-1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/oabhb8o1bnvyboc8qfguq74fe2to0elswn.png)
Differentiate with respect to x.
![(dy)/(dx)=(1)/(2)(1)/(√(3x-1))*3](https://img.qammunity.org/2023/formulas/mathematics/high-school/inpp6t2bdk1wefq7pmnmaiaq5e6vhlcfz3.png)
![(dy)/(dx)=(3)/(2√(3x-1))](https://img.qammunity.org/2023/formulas/mathematics/high-school/u5g0sszpczu1mzwkt6zpr69wipa60l3y9l.png)
![(dy)/(dx)=(3)/(2√(3x-1))>0](https://img.qammunity.org/2023/formulas/mathematics/high-school/324s2d1m1cg44whivpsenczkgj6hityb81.png)
![The\text{ function is increasing}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dc5gztdul5objypwg1dj7bpfsxs275kkzy.png)
We know that dy/dx is the rate of the given function.
Differentiate dy/dx with respect to x.
![(d^2y)/(dc^2)=-(1)/(2)*(3)/(2(3x-1)^(3\/2))*3](https://img.qammunity.org/2023/formulas/mathematics/high-school/49ysgzslrb2fn7t1ppb2tmcq7t9lcm4k7a.png)
![(d^2y)/(dc^2)=(-9)/(4(3x-1)^(3\/2))<0](https://img.qammunity.org/2023/formulas/mathematics/high-school/9zuc629a4nh3rr5aa2lwflo7m2arulpju2.png)
![The\text{ rate is decreasing}](https://img.qammunity.org/2023/formulas/mathematics/high-school/1h8wre1xen48g7nrv0y86yzdn48xc90sl6.png)
The function is increasing, and the rate is decreasing.
Final answer:
Increasing at a decreasing rate.