Question

Which one has the largest minor arc? (Blue arc) 80 279.5° (5x + 29)

Answer 1

the first blue arc is 80°

for the second one we get

`2x+7x-9=360\rightarrow9x=351\rightarrow x=(351)/(9)=39`

therefore the blue arc is 78°

for the third circle we get that blue arc is:

`360-279.5=80.5^(\circ)`

for the last one we get:

`5x+29+2x-19=360\rightarrow7x=350\rightarrow x=(350)/(7)=50`

so the arc is:

`100-19=81`

so the largest minor arc is the one that measure 81. So the last circle