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12. Diseases tend to spread exponentially. In the early days of AIDS, the growth rate was around 190%. In 1983, about 1700 people in the US died of AIDS. If the trend had continued unchecked, how many people would have died from AIDS in 1990?people

12. Diseases tend to spread exponentially. In the early days of AIDS, the growth rate-example-1

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SOLUTION

The formula for exponential growth is given as


\begin{gathered} f(x)=a(1+r)^x \\ \text{where } \\ a=initial\text{ amount } \\ r=\text{growth rate } \\ x=\text{ numer of years } \end{gathered}

From the question, the given parameters are


\begin{gathered} \text{ a=1700} \\ r=(190)/(100)=1.9 \\ x=1990-1983=7 \\ let\text{ number of people in that would have died in 1990 be y} \end{gathered}

Then replace the parameters in the formula above


\begin{gathered} y=1700(1+1.9)^7 \\ \\ y=1700(2.9)^7 \\ \text{then} \\ y=1700*1724.987 \\ y=2932479 \end{gathered}

Hence

The number of people that would have died from Aids in 1990 will be 2932479

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