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How many atoms of germanium are present in a sample containing 4.20 moles Ge

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Step-by-step explanation:

We have to find the number of Ge atoms present in a sample that contains 4.20 moles of Ge. By definition we know that 1 mol of Ge atoms contains 6.022 *10^23 atoms of it. We can use that ratio to find the answer to our problem.

1 mol of Ge : 6.022 *10^23 atoms

number of atoms = 4.20 moles of Ge * 6.022 *10^23 atoms/(1 mol of Ge)

number of atoms = 2.53 *10^24 atoms

Answer: 2.53 *10^24 atoms of Ge are present in 4.20 moles of it.

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